16=4+3(y+2)

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Solution for 16=4+3(y+2) equation: 



16=4+3(y+2)

We move all terms to the left:

16-(4+3(y+2))=0



We calculate terms in parentheses: -(4+3(y+2)), so:

4+3(y+2)

determiningTheFunctionDomain
3(y+2)+4

We multiply parentheses

3y+6+4

We add all the numbers together, and all the variables

3y+10

Back to the equation:

-(3y+10)



We get rid of parentheses

-3y-10+16=0

We add all the numbers together, and all the variables

-3y+6=0

We move all terms containing y to the left, all other terms to the right

-3y=-6

y=-6/-3

y=+2

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