3(x+2)+5(x+4)=42

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Solution for 3(x+2)+5(x+4)=42 equation: 



3(x+2)+5(x+4)=42

We move all terms to the left:

3(x+2)+5(x+4)-(42)=0

We multiply parentheses

3x+5x+6+20-42=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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