16=3(v-8)5v

Solution for 16=3(v-8)5v equation:

16=3(v-8)5v

We move all terms to the left:

16-(3(v-8)5v)=0


We calculate terms in parentheses: -(3(v-8)5v), so:

3(v-8)5v

We multiply parentheses

15v^2-120v

Back to the equation:

-(15v^2-120v)


We get rid of parentheses

-15v^2+120v+16=0

a = -15; b = 120; c = +16;
Δ = b2-4ac
Δ = 1202-4·(-15)·16
Δ = 15360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15360}=\sqrt{1024*15}=\sqrt{1024}*\sqrt{15}=32\sqrt{15}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-32\sqrt{15}}{2*-15}=\frac{-120-32\sqrt{15}}{-30}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+32\sqrt{15}}{2*-15}=\frac{-120+32\sqrt{15}}{-30}
$