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12-1/2x=x
We move all terms to the left:
12-1/2x-(x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1x-1/2x+12=0
We multiply all the terms by the denominator
-1x*2x+12*2x-1=0
Wy multiply elements
-2x^2+24x-1=0
a = -2; b = 24; c = -1;
Δ = b2-4ac
Δ = 242-4·(-2)·(-1)
Δ = 568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{568}=\sqrt{4*142}=\sqrt{4}*\sqrt{142}=2\sqrt{142}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{142}}{2*-2}=\frac{-24-2\sqrt{142}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{142}}{2*-2}=\frac{-24+2\sqrt{142}}{-4} $
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