16=2+a(2)

Solution for 16=2+a(2) equation:

16=2+a(2)

We move all terms to the left:

16-(2+a(2))=0

We add all the numbers together, and all the variables

-(+a^2+2)+16=0

We get rid of parentheses

-a^2-2+16=0

We add all the numbers together, and all the variables

-1a^2+14=0

a = -1; b = 0; c = +14;
Δ = b2-4ac
Δ = 02-4·(-1)·14
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{14}}{2*-1}=\frac{0-2\sqrt{14}}{-2}
=-\frac{2\sqrt{14}}{-2}
=-\frac{\sqrt{14}}{-1}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{14}}{2*-1}=\frac{0+2\sqrt{14}}{-2}
=\frac{2\sqrt{14}}{-2}
=\frac{\sqrt{14}}{-1}
$