-16k+4k=10k(2+k)

Solution for -16k+4k=10k(2+k) equation:

-16k+4k=10k(2+k)

We move all terms to the left:

-16k+4k-(10k(2+k))=0

We add all the numbers together, and all the variables

-16k+4k-(10k(k+2))=0

We add all the numbers together, and all the variables

-12k-(10k(k+2))=0


We calculate terms in parentheses: -(10k(k+2)), so:

10k(k+2)

We multiply parentheses

10k^2+20k

Back to the equation:

-(10k^2+20k)


We get rid of parentheses

-10k^2-12k-20k=0

We add all the numbers together, and all the variables

-10k^2-32k=0

a = -10; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·(-10)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*-10}=\frac{0}{-20}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*-10}=\frac{64}{-20}
=-3+1/5
$