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16=1/3(4-x)
We move all terms to the left:
16-(1/3(4-x))=0
Domain of the equation: 3(4-x))!=0We add all the numbers together, and all the variables
x∈R
-(1/3(-1x+4))+16=0
We multiply all the terms by the denominator
-(1+16*3(-1x+4))=0
We calculate terms in parentheses: -(1+16*3(-1x+4)), so:
1+16*3(-1x+4)
determiningTheFunctionDomain 16*3(-1x+4)+1
Wy multiply elements
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We use the square of the difference formula
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Back to the equation:
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