1/12(48-24b)=2(17-4b)

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Solution for 1/12(48-24b)=2(17-4b) equation: 



1/12(48-24b)=2(17-4b)

We move all terms to the left:

1/12(48-24b)-(2(17-4b))=0



Domain of the equation: 12(48-24b)!=0

b∈R



We add all the numbers together, and all the variables

1/12(-24b+48)-(2(-4b+17))=0

We multiply all the terms by the denominator


-((2(-4b+17)))*12(-24b+48)+1=0



We calculate terms in parentheses: -((2(-4b+17)))*12(-24b+48), so:

(2(-4b+17)))*12(-24b+48

We add all the numbers together, and all the variables

-24b+(2(-4b+17)))*12(+48

Back to the equation:

-(-24b+(2(-4b+17)))*12(+48)



We add all the numbers together, and all the variables

-(-24b+(2(-4b+17)))*1248+1=0

We move all terms containing b to the left, all other terms to the right

-(-24b+(2(-4b+17)))*1248=-1

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