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16=(2-3x)(x)
We move all terms to the left:
16-((2-3x)(x))=0
We add all the numbers together, and all the variables
-((-3x+2)x)+16=0
We calculate terms in parentheses: -((-3x+2)x), so:We get rid of parentheses
(-3x+2)x
We multiply parentheses
-3x^2+2x
Back to the equation:
-(-3x^2+2x)
3x^2-2x+16=0
a = 3; b = -2; c = +16;
Δ = b2-4ac
Δ = -22-4·3·16
Δ = -188
Delta is less than zero, so there is no solution for the equation
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