4(3x-5)=2x+40

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Solution for 4(3x-5)=2x+40 equation: 



4(3x-5)=2x+40

We move all terms to the left:

4(3x-5)-(2x+40)=0

We multiply parentheses

12x-(2x+40)-20=0

We get rid of parentheses

12x-2x-40-20=0

We add all the numbers together, and all the variables

10x-60=0

We move all terms containing x to the left, all other terms to the right

10x=60

x=60/10

x=6

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