164+(3x-6)2x=360

Solution for 164+(3x-6)2x=360 equation:

164+(3x-6)2x=360

We move all terms to the left:

164+(3x-6)2x-(360)=0

We add all the numbers together, and all the variables

(3x-6)2x-196=0

We multiply parentheses

6x^2-12x-196=0

a = 6; b = -12; c = -196;
Δ = b2-4ac
Δ = -122-4·6·(-196)
Δ = 4848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4848}=\sqrt{16*303}=\sqrt{16}*\sqrt{303}=4\sqrt{303}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{303}}{2*6}=\frac{12-4\sqrt{303}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{303}}{2*6}=\frac{12+4\sqrt{303}}{12}
$