160=w(2w-4)

Solution for 160=w(2w-4) equation:

160=w(2w-4)

We move all terms to the left:

160-(w(2w-4))=0


We calculate terms in parentheses: -(w(2w-4)), so:

w(2w-4)

We multiply parentheses

2w^2-4w

Back to the equation:

-(2w^2-4w)


We get rid of parentheses

-2w^2+4w+160=0

a = -2; b = 4; c = +160;
Δ = b2-4ac
Δ = 42-4·(-2)·160
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-36}{2*-2}=\frac{-40}{-4}
=+10
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+36}{2*-2}=\frac{32}{-4}
=-8
$