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1600=y(y-2)
We move all terms to the left:
1600-(y(y-2))=0
We calculate terms in parentheses: -(y(y-2)), so:We get rid of parentheses
y(y-2)
We multiply parentheses
y^2-2y
Back to the equation:
-(y^2-2y)
-y^2+2y+1600=0
We add all the numbers together, and all the variables
-1y^2+2y+1600=0
a = -1; b = 2; c = +1600;
Δ = b2-4ac
Δ = 22-4·(-1)·1600
Δ = 6404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6404}=\sqrt{4*1601}=\sqrt{4}*\sqrt{1601}=2\sqrt{1601}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1601}}{2*-1}=\frac{-2-2\sqrt{1601}}{-2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1601}}{2*-1}=\frac{-2+2\sqrt{1601}}{-2} $
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