16/4b=4b

Solution for 16/4b=4b equation:

16/4b=4b

We move all terms to the left:

16/4b-(4b)=0


Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R


We add all the numbers together, and all the variables

-4b+16/4b=0

We multiply all the terms by the denominator


-4b*4b+16=0

Wy multiply elements

-16b^2+16=0

a = -16; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-16)·16
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*-16}=\frac{-32}{-32}
=1
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*-16}=\frac{32}{-32}
=-1
$