-(2x+2)-1=-x-x(x+3)

Solution for -(2x+2)-1=-x-x(x+3) equation:

-(2x+2)-1=-x-x(x+3)

We move all terms to the left:

-(2x+2)-1-(-x-x(x+3))=0

We get rid of parentheses

-2x-(-x-x(x+3))-2-1=0


We calculate terms in parentheses: -(-x-x(x+3)), so:

-x-x(x+3)

We add all the numbers together, and all the variables

-1x-x(x+3)

We multiply parentheses

-x^2-1x-3x

We add all the numbers together, and all the variables

-1x^2-4x

Back to the equation:

-(-1x^2-4x)


We add all the numbers together, and all the variables

-(-1x^2-4x)-2x-3=0

We get rid of parentheses

1x^2+4x-2x-3=0

We add all the numbers together, and all the variables

x^2+2x-3=0

a = 1; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·1·(-3)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4}{2*1}=\frac{-6}{2}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4}{2*1}=\frac{2}{2}
=1
$