16-2x=4(1/4x-2)

Solution for 16-2x=4(1/4x-2) equation:

16-2x=4(1/4x-2)

We move all terms to the left:

16-2x-(4(1/4x-2))=0


Domain of the equation: 4x-2))!=0

x∈R


We multiply all the terms by the denominator


-2x*4x+16*4x-2))-(4(1-2))=0

We add all the numbers together, and all the variables

-2x*4x+16*4x-2))-(4(-1))=0

We add all the numbers together, and all the variables

-2x*4x+16*4x=0

Wy multiply elements

-8x^2+64x=0

a = -8; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·(-8)·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*-8}=\frac{-128}{-16}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*-8}=\frac{0}{-16}
=0
$