16-(7s+3)=8(1-s)

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Solution for 16-(7s+3)=8(1-s) equation: 



16-(7s+3)=8(1-s)

We move all terms to the left:

16-(7s+3)-(8(1-s))=0

We add all the numbers together, and all the variables

-(7s+3)-(8(-1s+1))+16=0

We get rid of parentheses

-7s-(8(-1s+1))-3+16=0



We calculate terms in parentheses: -(8(-1s+1)), so:

8(-1s+1)

We multiply parentheses

-8s+8

Back to the equation:

-(-8s+8)



We add all the numbers together, and all the variables

-7s-(-8s+8)+13=0

We get rid of parentheses

-7s+8s-8+13=0

We add all the numbers together, and all the variables

s+5=0

We move all terms containing s to the left, all other terms to the right

s=-5

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