-5(2y-2)+3y=7(y+2)

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Solution for -5(2y-2)+3y=7(y+2) equation: 



-5(2y-2)+3y=7(y+2)

We move all terms to the left:

-5(2y-2)+3y-(7(y+2))=0

We add all the numbers together, and all the variables

3y-5(2y-2)-(7(y+2))=0

We multiply parentheses

3y-10y-(7(y+2))+10=0



We calculate terms in parentheses: -(7(y+2)), so:

7(y+2)

We multiply parentheses

7y+14

Back to the equation:

-(7y+14)



We add all the numbers together, and all the variables

-7y-(7y+14)+10=0

We get rid of parentheses

-7y-7y-14+10=0

We add all the numbers together, and all the variables

-14y-4=0

We move all terms containing y to the left, all other terms to the right

-14y=4

y=4/-14

y=-2/7

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