16+42(6-x)=15-4(x+2

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Solution for 16+42(6-x)=15-4(x+2 equation: 



16+42(6-x)=15-4(x+2

We move all terms to the left:

16+42(6-x)-(15-4(x+2)=0

We add all the numbers together, and all the variables

42(-1x+6)-(15-4(x+2)+16=0

We multiply parentheses

-42x-(15-4(x+2)+16+252=0

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