16+2x=4(-x+3)-20

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Solution for 16+2x=4(-x+3)-20 equation: 



16+2x=4(-x+3)-20

We move all terms to the left:

16+2x-(4(-x+3)-20)=0

We add all the numbers together, and all the variables

2x-(4(-1x+3)-20)+16=0



We calculate terms in parentheses: -(4(-1x+3)-20), so:

4(-1x+3)-20

We multiply parentheses

-4x+12-20

We add all the numbers together, and all the variables

-4x-8

Back to the equation:

-(-4x-8)



We get rid of parentheses

2x+4x+8+16=0

We add all the numbers together, and all the variables

6x+24=0

We move all terms containing x to the left, all other terms to the right

6x=-24

x=-24/6

x=-4

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