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x2+8x-209=0
We add all the numbers together, and all the variables
x^2+8x-209=0
a = 1; b = 8; c = -209;
Δ = b2-4ac
Δ = 82-4·1·(-209)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-30}{2*1}=\frac{-38}{2} =-19 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+30}{2*1}=\frac{22}{2} =11 $
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