16(y-7)+12y=18y-40

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Solution for 16(y-7)+12y=18y-40 equation: 



16(y-7)+12y=18y-40

We move all terms to the left:

16(y-7)+12y-(18y-40)=0

We add all the numbers together, and all the variables

12y+16(y-7)-(18y-40)=0

We multiply parentheses

12y+16y-(18y-40)-112=0

We get rid of parentheses

12y+16y-18y+40-112=0

We add all the numbers together, and all the variables

10y-72=0

We move all terms containing y to the left, all other terms to the right

10y=72

y=72/10

y=7+1/5

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