3(2y-7)+14=9(2y+1)-4

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Solution for 3(2y-7)+14=9(2y+1)-4 equation: 



3(2y-7)+14=9(2y+1)-4

We move all terms to the left:

3(2y-7)+14-(9(2y+1)-4)=0

We multiply parentheses

6y-(9(2y+1)-4)-21+14=0



We calculate terms in parentheses: -(9(2y+1)-4), so:

9(2y+1)-4

We multiply parentheses

18y+9-4

We add all the numbers together, and all the variables

18y+5

Back to the equation:

-(18y+5)



We add all the numbers together, and all the variables

6y-(18y+5)-7=0

We get rid of parentheses

6y-18y-5-7=0

We add all the numbers together, and all the variables

-12y-12=0

We move all terms containing y to the left, all other terms to the right

-12y=12

y=12/-12

y=-1

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