16(x-2.5)=3(3x+5)+1

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Solution for 16(x-2.5)=3(3x+5)+1 equation: 



16(x-2.5)=3(3x+5)+1

We move all terms to the left:

16(x-2.5)-(3(3x+5)+1)=0

We multiply parentheses

16x-(3(3x+5)+1)-40=0



We calculate terms in parentheses: -(3(3x+5)+1), so:

3(3x+5)+1

We multiply parentheses

9x+15+1

We add all the numbers together, and all the variables

9x+16

Back to the equation:

-(9x+16)



We get rid of parentheses

16x-9x-16-40=0

We add all the numbers together, and all the variables

7x-56=0

We move all terms containing x to the left, all other terms to the right

7x=56

x=56/7

x=8

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