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3(3+2x)-(1-x)=2(4+3x)+x
We move all terms to the left:
3(3+2x)-(1-x)-(2(4+3x)+x)=0
We add all the numbers together, and all the variables
3(2x+3)-(-1x+1)-(2(3x+4)+x)=0
We multiply parentheses
6x-(-1x+1)-(2(3x+4)+x)+9=0
We get rid of parentheses
6x+1x-(2(3x+4)+x)-1+9=0
We calculate terms in parentheses: -(2(3x+4)+x), so:We add all the numbers together, and all the variables
2(3x+4)+x
We add all the numbers together, and all the variables
x+2(3x+4)
We multiply parentheses
x+6x+8
We add all the numbers together, and all the variables
7x+8
Back to the equation:
-(7x+8)
7x-(7x+8)+8=0
We get rid of parentheses
7x-7x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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