16(2x-3)=4(x+2)

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Solution for 16(2x-3)=4(x+2) equation: 



16(2x-3)=4(x+2)

We move all terms to the left:

16(2x-3)-(4(x+2))=0

We multiply parentheses

32x-(4(x+2))-48=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

32x-4x-8-48=0

We add all the numbers together, and all the variables

28x-56=0

We move all terms containing x to the left, all other terms to the right

28x=56

x=56/28

x=2

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