15y+32=2(10y-7)-5+46

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Solution for 15y+32=2(10y-7)-5+46 equation: 



15y+32=2(10y-7)-5+46

We move all terms to the left:

15y+32-(2(10y-7)-5+46)=0



We calculate terms in parentheses: -(2(10y-7)-5+46), so:

2(10y-7)-5+46

We add all the numbers together, and all the variables

2(10y-7)+41

We multiply parentheses

20y-14+41

We add all the numbers together, and all the variables

20y+27

Back to the equation:

-(20y+27)



We get rid of parentheses

15y-20y-27+32=0

We add all the numbers together, and all the variables

-5y+5=0

We move all terms containing y to the left, all other terms to the right

-5y=-5

y=-5/-5

y=1

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