If it's not what You are looking for type in the equation solver your own equation and let us solve it.
15x^2+5x=0
a = 15; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·15·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*15}=\frac{-10}{30} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*15}=\frac{0}{30} =0 $
| -6(7x+2)=-42x-12 | | 6+15x-8-8x=3x+2 | | 7x-13=32+2x | | -4(r+5)=-53 | | 180=b+(b+45)+90+(2b-90)+3/2b | | (x+2)/2=4-(x+1)/5 | | -3(a+4)=4a-5 | | -8(8+2x)+4(2-8x)=40 | | 9(x-3=12x | | 4(p-16)+3=19 | | 9x+14=-202 | | 8w+5-3w=8w-48w+5−3w=8w-4 | | 5k(3)+k=80 | | 2=j-10/3 | | -2x+3x=17 | | x+2x+4x=30000 | | -2(s-9)=-16 | | 16p²—64=0 | | 8w+5-3w=8w-48w+5−3w=8w−4 | | 20x+4-12x=16-6x-5 | | -3(n-2(-7(n+7=-13 | | 5(x+4)+x=3(x+3)+4 | | 165=25-x | | 53+(9x-15)=12x×1 | | 4-6n=-38 | | 2(r+6)=-18 | | -16=r | | -24x=-2 | | 6x+48+3x-10=7x+30 | | -9c+7=11c-25 | | 4p-11+8p-6=5p+4p+1 | | 2(-3y+7)-4=34 |