(x+2)/2=4-(x+1)/5

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Solution for (x+2)/2=4-(x+1)/5 equation: 



(x+2)/2=4-(x+1)/5

We move all terms to the left:

(x+2)/2-(4-(x+1)/5)=0

We calculate fractions


x/()+(-(4-(x+1)*2)/()=0



We calculate terms in parentheses: +(-(4-(x+1)*2)/(), so:

-(4-(x+1)*2)/(

We multiply all the terms by the denominator


-(4-(x+1)*2)



We calculate terms in parentheses: -(4-(x+1)*2), so:

4-(x+1)*2

determiningTheFunctionDomain
-(x+1)*2+4

We multiply parentheses

-2x-2+4

We add all the numbers together, and all the variables

-2x+2

Back to the equation:

-(-2x+2)



We get rid of parentheses

2x-2

Back to the equation:

+(2x-2)



We get rid of parentheses

x/()+2x-2=0

We multiply all the terms by the denominator


x+2x*()-2*()=0

We add all the numbers together, and all the variables

x+2x*()=0

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