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15x^2+16x=15
We move all terms to the left:
15x^2+16x-(15)=0
a = 15; b = 16; c = -15;
Δ = b2-4ac
Δ = 162-4·15·(-15)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-34}{2*15}=\frac{-50}{30} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+34}{2*15}=\frac{18}{30} =3/5 $
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