(17/5)x+(11/4)=7

Solution for (17/5)x+(11/4)=7 equation:

(17/5)x+(11/4)=7

We move all terms to the left:

(17/5)x+(11/4)-(7)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


determiningTheFunctionDomain
(17/5)x-7+(11/4)=0

We add all the numbers together, and all the variables

(+17/5)x-7+(+11/4)=0

We multiply parentheses

17x^2-7+(+11/4)=0

We get rid of parentheses

17x^2-7+11/4=0

We multiply all the terms by the denominator


17x^2*4+11-7*4=0

We add all the numbers together, and all the variables

17x^2*4-17=0

Wy multiply elements

68x^2-17=0

a = 68; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·68·(-17)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-68}{2*68}=\frac{-68}{136}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+68}{2*68}=\frac{68}{136}
=1/2
$