15x/5x-8(x-4)=16

Solution for 15x/5x-8(x-4)=16 equation:

15x/5x-8(x-4)=16

We move all terms to the left:

15x/5x-8(x-4)-(16)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We multiply parentheses

15x/5x-8x+32-16=0

We multiply all the terms by the denominator


15x-8x*5x+32*5x-16*5x=0

Wy multiply elements

-40x^2+15x+160x-80x=0

We add all the numbers together, and all the variables

-40x^2+95x=0

a = -40; b = 95; c = 0;
Δ = b2-4ac
Δ = 952-4·(-40)·0
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-95}{2*-40}=\frac{-190}{-80}
=2+3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+95}{2*-40}=\frac{0}{-80}
=0
$