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x+(x+4)/2+(2x-4)2=49
We move all terms to the left:
x+(x+4)/2+(2x-4)2-(49)=0
We multiply parentheses
x+(x+4)/2+4x-8-49=0
We multiply all the terms by the denominator
x*2+(x+4)+4x*2-8*2-49*2=0
We add all the numbers together, and all the variables
x*2+(x+4)+4x*2-114=0
Wy multiply elements
2x+(x+4)+8x-114=0
We get rid of parentheses
2x+x+8x+4-114=0
We add all the numbers together, and all the variables
11x-110=0
We move all terms containing x to the left, all other terms to the right
11x=110
x=110/11
x=10
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