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15x(x+2)=6x(2x+7)
We move all terms to the left:
15x(x+2)-(6x(2x+7))=0
We multiply parentheses
15x^2+30x-(6x(2x+7))=0
We calculate terms in parentheses: -(6x(2x+7)), so:We get rid of parentheses
6x(2x+7)
We multiply parentheses
12x^2+42x
Back to the equation:
-(12x^2+42x)
15x^2-12x^2+30x-42x=0
We add all the numbers together, and all the variables
3x^2-12x=0
a = 3; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·3·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*3}=\frac{24}{6} =4 $
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