6(r+2)=3(2r-3)

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Solution for 6(r+2)=3(2r-3) equation: 



6(r+2)=3(2r-3)

We move all terms to the left:

6(r+2)-(3(2r-3))=0

We multiply parentheses

6r-(3(2r-3))+12=0



We calculate terms in parentheses: -(3(2r-3)), so:

3(2r-3)

We multiply parentheses

6r-9

Back to the equation:

-(6r-9)



We get rid of parentheses

6r-6r+9+12=0

We add all the numbers together, and all the variables

21!=0

There is no solution for this equation

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