15m+(12m/2m)=

Solution for 15m+(12m/2m)= equation:

15m+(12m/2m)=

We move all terms to the left:

15m+(12m/2m)-()=0


Domain of the equation: 2m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

15m+(+12m/2m)-()=0

We add all the numbers together, and all the variables

15m+(+12m/2m)=0

We get rid of parentheses

15m+12m/2m=0

We multiply all the terms by the denominator


15m*2m+12m=0

We add all the numbers together, and all the variables

12m+15m*2m=0

Wy multiply elements

30m^2+12m=0

a = 30; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·30·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*30}=\frac{-24}{60}
=-2/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*30}=\frac{0}{60}
=0
$