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15=3/4(9z+8)
We move all terms to the left:
15-(3/4(9z+8))=0
Domain of the equation: 4(9z+8))!=0We multiply all the terms by the denominator
z∈R
-(3+15*4(9z+8))=0
We calculate terms in parentheses: -(3+15*4(9z+8)), so:We add all the numbers together, and all the variables
3+15*4(9z+8)
determiningTheFunctionDomain 15*4(9z+8)+3
Wy multiply elements
60z(9+3
Back to the equation:
-(60z(9+3)
-(60z12=0
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