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-24=5w(w-4)-7w
We move all terms to the left:
-24-(5w(w-4)-7w)=0
We calculate terms in parentheses: -(5w(w-4)-7w), so:We get rid of parentheses
5w(w-4)-7w
We add all the numbers together, and all the variables
-7w+5w(w-4)
We multiply parentheses
5w^2-7w-20w
We add all the numbers together, and all the variables
5w^2-27w
Back to the equation:
-(5w^2-27w)
-5w^2+27w-24=0
a = -5; b = 27; c = -24;
Δ = b2-4ac
Δ = 272-4·(-5)·(-24)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{249}}{2*-5}=\frac{-27-\sqrt{249}}{-10} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{249}}{2*-5}=\frac{-27+\sqrt{249}}{-10} $
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