15=3(c-2)-6c

Solution for 15=3(c-2)-6c equation:

15=3(c-2)-6c

We move all terms to the left:

15-(3(c-2)-6c)=0


We calculate terms in parentheses: -(3(c-2)-6c), so:

3(c-2)-6c

We add all the numbers together, and all the variables

-6c+3(c-2)

We multiply parentheses

-6c+3c-6

We add all the numbers together, and all the variables

-3c-6

Back to the equation:

-(-3c-6)


We get rid of parentheses

3c+6+15=0

We add all the numbers together, and all the variables

3c+21=0

We move all terms containing c to the left, all other terms to the right

3c=-21

c=-21/3

c=-7