15=2(2+4z)+3

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Solution for 15=2(2+4z)+3 equation: 



15=2(2+4z)+3

We move all terms to the left:

15-(2(2+4z)+3)=0

We add all the numbers together, and all the variables

-(2(4z+2)+3)+15=0



We calculate terms in parentheses: -(2(4z+2)+3), so:

2(4z+2)+3

We multiply parentheses

8z+4+3

We add all the numbers together, and all the variables

8z+7

Back to the equation:

-(8z+7)



We get rid of parentheses

-8z-7+15=0

We add all the numbers together, and all the variables

-8z+8=0

We move all terms containing z to the left, all other terms to the right

-8z=-8

z=-8/-8

z=1

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