43x2+7=43

Solution for 43x2+7=43 equation:

43x^2+7=43

We move all terms to the left:

43x^2+7-(43)=0

We add all the numbers together, and all the variables

43x^2-36=0

a = 43; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·43·(-36)
Δ = 6192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6192}=\sqrt{144*43}=\sqrt{144}*\sqrt{43}=12\sqrt{43}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{43}}{2*43}=\frac{0-12\sqrt{43}}{86}
=-\frac{12\sqrt{43}}{86}
=-\frac{6\sqrt{43}}{43}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{43}}{2*43}=\frac{0+12\sqrt{43}}{86}
=\frac{12\sqrt{43}}{86}
=\frac{6\sqrt{43}}{43}
$