15=1/2(4b-6)

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Solution for 15=1/2(4b-6) equation: 



15=1/2(4b-6)

We move all terms to the left:

15-(1/2(4b-6))=0



Domain of the equation: 2(4b-6))!=0

b∈R



We multiply all the terms by the denominator


-(1+15*2(4b-6))=0



We calculate terms in parentheses: -(1+15*2(4b-6)), so:

1+15*2(4b-6)

determiningTheFunctionDomain
15*2(4b-6)+1

Wy multiply elements

30b(4+1

Back to the equation:

-(30b(4+1)



We add all the numbers together, and all the variables

-(30b5=0

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