5c+4(c-1)=2+5(2+c)

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Solution for 5c+4(c-1)=2+5(2+c) equation: 



5c+4(c-1)=2+5(2+c)

We move all terms to the left:

5c+4(c-1)-(2+5(2+c))=0

We add all the numbers together, and all the variables

5c+4(c-1)-(2+5(c+2))=0

We multiply parentheses

5c+4c-(2+5(c+2))-4=0



We calculate terms in parentheses: -(2+5(c+2)), so:

2+5(c+2)

determiningTheFunctionDomain
5(c+2)+2

We multiply parentheses

5c+10+2

We add all the numbers together, and all the variables

5c+12

Back to the equation:

-(5c+12)



We add all the numbers together, and all the variables

9c-(5c+12)-4=0

We get rid of parentheses

9c-5c-12-4=0

We add all the numbers together, and all the variables

4c-16=0

We move all terms containing c to the left, all other terms to the right

4c=16

c=16/4

c=4

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