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151=235t-16t^2
We move all terms to the left:
151-(235t-16t^2)=0
We get rid of parentheses
16t^2-235t+151=0
a = 16; b = -235; c = +151;
Δ = b2-4ac
Δ = -2352-4·16·151
Δ = 45561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-235)-\sqrt{45561}}{2*16}=\frac{235-\sqrt{45561}}{32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-235)+\sqrt{45561}}{2*16}=\frac{235+\sqrt{45561}}{32} $
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