1/2(2x-8)-(2x+4)=3+2(x+2)

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Solution for 1/2(2x-8)-(2x+4)=3+2(x+2) equation:



1/2(2x-8)-(2x+4)=3+2(x+2)
We move all terms to the left:
1/2(2x-8)-(2x+4)-(3+2(x+2))=0
Domain of the equation: 2(2x-8)!=0
x∈R
We get rid of parentheses
1/2(2x-8)-2x-(3+2(x+2))-4=0
We multiply all the terms by the denominator
-2x*2(2x-8)-((3+2(x+2)))*2(2x-8)-4*2(2x-8)+1=0
We calculate terms in parentheses: -((3+2(x+2)))*2(2x-8), so:
(3+2(x+2)))*2(2x-8
Wy multiply elements
-4x^2(2-((3+2(x+2)))*2(2x-8)-8x(2+1=0

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