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1512=(120-2x)*x
We move all terms to the left:
1512-((120-2x)*x)=0
We add all the numbers together, and all the variables
-((-2x+120)*x)+1512=0
We calculate terms in parentheses: -((-2x+120)*x), so:We get rid of parentheses
(-2x+120)*x
We multiply parentheses
-2x^2+120x
Back to the equation:
-(-2x^2+120x)
2x^2-120x+1512=0
a = 2; b = -120; c = +1512;
Δ = b2-4ac
Δ = -1202-4·2·1512
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-48}{2*2}=\frac{72}{4} =18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+48}{2*2}=\frac{168}{4} =42 $
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