(x+1)/(2x+3)=65x-1)/(7x+3)

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Solution for (x+1)/(2x+3)=65x-1)/(7x+3) equation: 



(x+1)/(2x+3)=65x-1)/(7x+3)

We move all terms to the left:

(x+1)/(2x+3)-(65x-1)/(7x+3))=0



Domain of the equation: (2x+3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-3

x!=-3/2

x!=-1+1/2

x∈R





Domain of the equation: (7x+3))!=0

x∈R



We calculate fractions


((x+1)*(7x+3)))/((2x+3)*(7x+3)))+(-(65x-1)*(2x+3))/((2x+3)*(7x+3)))=0

We add all the numbers together, and all the variables

((x+1)*(7x+3)))/((2x+3)*(7x+3)))+(-(65x-1)*(2x+3))/((2x+3)*(7x=0

We calculate fractions


-1)*(2x+3)*(7x+(((x+1)*(7x+3)))*(2x/(((2x+3)*(7x+3)))+(-(65x*(2x+3)*((2x+3)*(7x+3)))+(-65x/(((2x+3)*(7x+3)))+(-(65x*(2x=0

We can not solve this equation

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