150-5t=5t2

Solution for 150-5t=5t2 equation:

150-5t=5t^2

We move all terms to the left:

150-5t-(5t^2)=0

determiningTheFunctionDomain
-5t^2-5t+150=0

a = -5; b = -5; c = +150;
Δ = b2-4ac
Δ = -52-4·(-5)·150
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-55}{2*-5}=\frac{-50}{-10}
=+5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+55}{2*-5}=\frac{60}{-10}
=-6
$