4(4x-2)+1=16x-74(4x-2)+1=16x-7

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Solution for 4(4x-2)+1=16x-74(4x-2)+1=16x-7 equation: 



4(4x-2)+1=16x-74(4x-2)+1=16x-7

We move all terms to the left:

4(4x-2)+1-(16x-74(4x-2)+1)=0

We multiply parentheses

16x-(16x-74(4x-2)+1)-8+1=0



We calculate terms in parentheses: -(16x-74(4x-2)+1), so:

16x-74(4x-2)+1

We multiply parentheses

16x-296x+148+1

We add all the numbers together, and all the variables

-280x+149

Back to the equation:

-(-280x+149)



We add all the numbers together, and all the variables

16x-(-280x+149)-7=0

We get rid of parentheses

16x+280x-149-7=0

We add all the numbers together, and all the variables

296x-156=0

We move all terms containing x to the left, all other terms to the right

296x=156

x=156/296

x=39/74

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