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15/16m-3/4m=15
We move all terms to the left:
15/16m-3/4m-(15)=0
Domain of the equation: 16m!=0
m!=0/16
m!=0
m∈R
Domain of the equation: 4m!=0We calculate fractions
m!=0/4
m!=0
m∈R
60m/64m^2+(-48m)/64m^2-15=0
We multiply all the terms by the denominator
60m+(-48m)-15*64m^2=0
Wy multiply elements
-960m^2+60m+(-48m)=0
We get rid of parentheses
-960m^2+60m-48m=0
We add all the numbers together, and all the variables
-960m^2+12m=0
a = -960; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-960)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-960}=\frac{-24}{-1920} =1/80 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-960}=\frac{0}{-1920} =0 $
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